If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

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Aicharya · Accepted Answer

By Rutherford's experiment $\begin{aligned} R_1 & =R_0 A_1^{1 / 3} \ R_2 & =R_0 A_2^{1 / 3} \end{aligned}$ Given $\begin{aligned} R_1 & =1.5 	ext { fermi } \ A_1 & =125 \ A_2 & =64 \ R_2 & =? \end{aligned}$ Now, $\frac{R_1}{R_2}=\left(\frac{A_1}{A_2}ight)^{1 / 3} \quad$ [from the Eqs. (i) and (ii)] $\begin{aligned} & \frac{1.5}{R_2}=\left(\frac{125}{64}ight)^{1 / 3} \ & \Rightarrow \quad \frac{1.5}{R_2}=\frac{5}{4} \ & \Rightarrow \quad R_2=\frac{1.5 	imes 4}{5}=0.3 	imes 4 \ & =1.2 	ext { fermi } \end{aligned}$

If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

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