If the probability of hitting a target by a shooter, in any shot is 1 3 , then the minimum number of independent shots at the target required by him so that the probability of hitting the target at least once is greater than 5 6 , is:

Question

Aicharya · Accepted Answer

P hitting &#8201; target = 1 3 Let number of trials = n P h i t t i n g &#8201;&#8201; t a r g e t &#8201;&#8201; a t l e a s t &#8201; o n c e = 1 - P not &#160; hit = 1 - 2 3 n &#62; 5 6 &#8658; 1 6 &#62; 2 3 n So minimum number of trials = 5

If the probability of hitting a target by a shooter, in any shot is 1 3 , then the minimum number of…

Solution