Then $F(0)$ is equal toIf the probability distribution function of a random variable $\mathrm{X}$ is given as Then $F(0)$ is equal to
Then $F(0)$ is equal to- $P(X>0)$
- $1-P(X>0)$
- $1-\mathrm{P}(\mathrm{X} < 0)$
- $\mathrm{P}(\mathrm{X} < 0)$
Solution
$\begin{aligned} & \therefore F(0)=1-[P(x=1)+P(x=2)] \\ & =1-P(X>0)\end{aligned}$Asked in: MHT CET 2021 (23 Sep Shift 1)