If the population grows at the rate $5 \%$ peryear, then the time taken for the population to become double…

If the population grows at the rate $5 \%$ peryear, then the time taken for the population to become double is $\quad$ (Given $\log 2=0.6912$ )
  1. $13.8275$ years
  2. $13.624$ years
  3. 13.725 years
  4. $13.8240$ years

Solution

Let initial population $=P_{0}$ and let $P$ be the population at time $t$ We have $\frac{\mathrm{dP}}{\mathrm{dt}}=\frac{5 \mathrm{P}}{100}$ $\therefore \frac{d P}{d t}=\frac{P}{20} \Rightarrow \int \frac{d P}{P}=\int \frac{1}{20} d t$ $\therefore \log P=\frac{1}{20} t+C$....(1) When $t=0, P=P_{0}$ $\therefore \log \mathrm{P}_{0}=0+\mathrm{C} \Rightarrow \mathrm{C}=\log \mathrm{P}_{0}$ From (1), $\log \left(\frac{P}{P_{0}}\right)=\frac{t}{20}$....(2) When $P=2 P_{0}$, we get $\log 2=\frac{t}{20} \Rightarrow t=20(\log 2)=20 \times 0.6912=13.8240$ years

Asked in: MHT CET 2020 (14 Oct Shift 2)

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