If the polar co-ordinates of a point are $\left(2, \frac{\pi^c}{4}\right)$, then its Cartesian co-ordinates are

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Aicharya · Accepted Answer

Let the Cartesian coordinates by $(\mathrm{x}, \mathrm{y})$ We have $\sqrt{x^2+y^2}=2 \Rightarrow x^2+y^2=4$ and $	an \frac{\pi}{4}=\frac{y}{x} \Rightarrow 1=\frac{y}{x} \Rightarrow x=y$ $	herefore 2 x^2=4 \Rightarrow x^2=2 \Rightarrow x= \pm \sqrt{2} \Rightarrow y= \pm \sqrt{2}$

If the polar co-ordinates of a point are $\left(2, \frac{\pi^c}{4}\right)$, then its Cartesian co-ordinates…

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