If the planes $2 x-5 y+z=8$ and $2 \lambda x-15 y+\lambda z+6=0$ are parallel to each other, then value of $\lambda$ is

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Aicharya · Accepted Answer

Given planes are parallel. Therefore normal vector to their plane is also parallel. $	herefore \frac{2}{2 \lambda}=\frac{-5}{-15}=\frac{1}{\lambda} \Rightarrow \frac{1}{\lambda}=\frac{1}{3} \Rightarrow \lambda=3$

If the planes $2 x-5 y+z=8$ and $2 \lambda x-15 y+\lambda z+6=0$ are parallel to each other, then value of…

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