If the pK a of a weak acid HA is 4 .80 and the pK b of a weak base BOH is 4 .78 . Then, the pH of an aqueous…

If the pK a of a weak acid HA is 4 .80 and the pK b of a weak base BOH is 4 .78 . Then, the pH of an aqueous solution of the corresponding salt, BA will be
  1. 8.23
  2. 9.41
  3. 7.01
  4. 5.91

Solution

BOH + HA → B + + A − + H 2 O
pH = 1 2  pK w + 1 2   pK a − 1 2 pK b
=   1 2 14 + 4.80 − 4.78 = 7.01

Asked in: JEE-TOPICTESTS-CHEMISTRY

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