If the perpendicular distance from $(1,2,4)$ to the plane $2 x+2 y-z+k=0$ is 3 , then $k=$

Question

Aicharya · Accepted Answer

$\begin{aligned} & 2 x+2 y-z+k=0, P(1,2,4) \ & p=\left|\frac{2(1)+(2)(2)-(4)+k}{\sqrt{4+4+1}}ight| \Rightarrow 3=\left|\frac{2+k}{3}ight| \Rightarrow k=7 .\end{aligned}$

If the perpendicular distance from $(1,2,4)$ to the plane $2 x+2 y-z+k=0$ is 3 , then $k=$

Solution