If the pair of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 p x y-y^2=0$ be such that each pair bisects the…

If the pair of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 p x y-y^2=0$ be such that each pair bisects the angle between the other pair, then
  1. $p q=-1$
  2. $\mathrm{p}=\mathrm{q}$
  3. $p=-q$
  4. $\mathrm{pq}=1$

Solution

Equation of bisector of both pair of straight lines, $p x^2+2 x y-p y^2=0$
$q x^2+2 x y-q y^2=0$
From (1) and (2). $\frac{\mathrm{q}}{1}=\frac{2}{-2 \mathrm{p}}=\frac{-\mathrm{q}}{-1} \Rightarrow \mathrm{pq}=-1$

Asked in: JEE Main 2003

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