If the pair of lines represented by $3 x^2-5 x y+P y^2=0$ and $6 x^2-x y-5 y^2=0$ have one line in common,…
- $\frac{33}{4}$
- $\frac{17}{4}$
- $-\frac{33}{4}$
- $-\frac{17}{4}$
Solution
When $y=-\frac{6 x}{5} ; 3 x^2-5 x\left(\frac{-6 x}{5}\right)+\frac{36 x^2}{25} P=0$
$\Rightarrow 9+\frac{36 P}{25}=0 \Rightarrow P=\frac{-25}{4}$;
Sum of values of $P=2-\frac{25}{4}=\frac{-17}{4}$.
Asked in: AP EAMCET 2024 (21 May Shift 2)