If the orthocentre and the centroid of a triangle are $(-3,5,2)$ and $(3,3,4)$ respectively, then its…
If the orthocentre and the centroid of a triangle are $(-3,5,2)$ and $(3,3,4)$ respectively, then its circumcentre is
- $(6,2,5)$
- $(62,-5)$
- $(6,-2,5)$
- $(6,-2,-5)$
Solution
We know that, in a triangle, if $\mathrm{O}$ is orthocentre, $G$ is centroid and $S$ is circumcentre, then $\mathrm{SG}: \mathrm{G0}=1: 2$ Let circumcentre be $(x, y, z)$.
$
\begin{array}{ll}
\therefore & \left(\frac{-3+2 x}{1+2}, \frac{5+2 y}{1+2}, \frac{2+2 z}{1+2}\right)=(3,3,4) \\
\Rightarrow & \left(\frac{-3+2 x}{3}, \frac{5+2 y}{3}, \frac{2+2 z}{3}\right)=(3,3,4) \\
\Rightarrow & \frac{-3+2 x}{3}=3, \frac{5+2 y}{3}=3, \frac{2+2 z}{3}=4 \\
\Rightarrow & \quad x=6, y=2, z=5 \\
\therefore & S(6,2,5) .
\end{array}
$
Asked in: AP EAMCET 2018 (22 Apr Shift 1)
Practice more Three Dimensional Geometry questions on Aicharya