If the number of diagonals of a regular polygon of $n$ sides is 104 , then $\mathrm{n}=$
If the number of diagonals of a regular polygon of $n$ sides is 104 , then $\mathrm{n}=$
- 19
- 16
- 13
- 11
Solution
We know that, Number of diagonals of a regular
$
\begin{aligned}
& \text { polygon of } n \text { sides }=\frac{(n-3) n}{2} \\
& \Rightarrow \quad 104=\frac{(n-3) n}{2} \\
& \Rightarrow \quad n=16 \text { and } n=-13 \text { (Rejected) } \\
& \Rightarrow \quad n=16
\end{aligned}
$
Asked in: AP EAMCET 2023 (15 May Shift 1)
Practice more Binomial Theorem questions on Aicharya