If the normal to the curve $y=f(x)$ at the point $(3,4)$ makes and angle $\left(\frac{3 \pi}{4}\right)$ with positive $\mathrm{X}$-axis, then $f^{\prime}(3)$ is equal to

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Aicharya · Accepted Answer

$\begin{aligned} & 	ext { Slope of normal }=\frac{-1}{f^{\prime}(x)} \ & \Rightarrow 	an \left(\frac{3 \pi}{4}ight)=\frac{-1}{f^{\prime}(3)} \ & \Rightarrow-1=\frac{-1}{f^{\prime}(3)} \ & \Rightarrow f^{\prime}(3)=1\end{aligned}$

If the normal to the curve $y=f(x)$ at the point $(3,4)$ makes and angle $\left(\frac{3 \pi}{4}\right)$ with…

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