If the normal at the point $t_1$ (i.e., at $\left.\left(a t_1^2, 2 \mathrm{at}_1\right)\right)$ on $y^2=4 a…

If the normal at the point $t_1$ (i.e., at $\left.\left(a t_1^2, 2 \mathrm{at}_1\right)\right)$ on $y^2=4 a x$ meets the parabola again at the point $t_2$, then $t_1 t_2=$
  1. $-2-t_1^2$
  2. $-2$
  3. $-t_1^2+2$
  4. $t_1^2+2$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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