If the normal at one end of a latus rectum of the ellipse $\frac{x^2}{32}+\frac{y^2}{b^2}=1$ passes through…

If the normal at one end of a latus rectum of the ellipse $\frac{x^2}{32}+\frac{y^2}{b^2}=1$ passes through one end of the minor axis, then $\frac{e^4}{1-e^2}=$ (Here $e$ is the eccentricity of the ellipse)
  1. $\frac{1}{2}$
  2. $1$
  3. $\frac{2}{3}$
  4. $\frac{3}{2}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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