If the matrix $A=\left[\begin{array}{cccc}1 & 2 & 3 & 0 \\ 2 & 4 & 3 & 2 \\ 3 & 2 & 1 & 3 \\ 6 & 8 & 7 &…

If the matrix $A=\left[\begin{array}{cccc}1 & 2 & 3 & 0 \\ 2 & 4 & 3 & 2 \\ 3 & 2 & 1 & 3 \\ 6 & 8 & 7 & \alpha\end{array}\right]$ is of rank 3, then $\alpha$ equals to
  1. $-5$
  2. $5$
  3. $4$
  4. $1$

Solution

Given, $A=\left[\begin{array}{cccc}1 & 2 & 3 & 0 \\ 2 & 4 & 3 & 2 \\ 3 & 2 & 1 & 3 \\ 6 & 8 & 7 & \alpha\end{array}\right]$ Applying $R_2 \rightarrow R_2-2 R_1, \quad R_3 \rightarrow R_3-3 R_1 \quad$ and $ \begin{aligned} R_4 \rightarrow R_4 & -2 R_3 \\ = & {\left[\begin{array}{rrrr} 1 & 2 & 3 & 0 \\ 0 & 0 & -3 & 2 \\ 0 & -4 & -8 & 3 \\ 0 & 4 & 5 & \alpha-6 \end{array}\right] } \end{aligned} $ Applying $R_4 \rightarrow R_4+R_3$ $ =\left[\begin{array}{rrrr} 1 & 2 & 3 & 0 \\ 0 & 0 & -3 & 2 \\ 0 & -4 & -8 & 3 \\ 0 & 0 & -3 & \alpha-3 \end{array}\right] $ Applying $R_4 \rightarrow R_4-R_2$ $ =\left[\begin{array}{rrrr} 1 & 2 & 3 & 0 \\ 0 & 0 & -3 & 2 \\ 0 & -4 & -8 & 3 \\ 0 & 0 & 0 & \alpha-5 \end{array}\right] $ Since, the matrix $A$ is of rank 3 . $ \therefore \quad \alpha-5=0 \Rightarrow \alpha=5 $

Asked in: AP EAMCET 2014

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