If the matrix A = 0 2 K - 1 satisfies A A 3 + 3 I = 2 I , then the value of K is

If the matrix A=02K-1 satisfies AA3+3I=2I, then the value of K is
  1. 12
  2. 1
  3. -1
  4. -12

Solution

AA3+3I=2I

A2=02K-102K-1

=2K-2-K2K+1

A3=2K-2-K2K+10-1K2

=-2K4K+22K2+K-2K-2K-1

A4=2K-2-K2K+12K-2-K2K+1

=4K2+2K       -4K-4K-2-2K2-2K2-K  2K+4K2+1+4K

A4+3AI=2I

2I=4K2+2K-8K-2-4K2-K4K2+6K+1+302K-11001

2I=4K2+2K-8K-2-4K2-K4K2+6K+1+302K-1

2I=4K2+2K6-8K-23K-K-4K24K2+6K+1-3

  4-8K=0

K=12

Asked in: JEE Main 2021 (27 Aug Shift 1)

Practice more Matrices questions on Aicharya