If the mass defect of ${ }_5 \mathrm{~B}^{11}$ is $0.081 \mathrm{u}$, its average binding energy (in…

If the mass defect of ${ }_5 \mathrm{~B}^{11}$ is $0.081 \mathrm{u}$, its average binding energy (in $\mathrm{MeV}$ ) is
  1. $8.60$
  2. $6.85$
  3. $5.60$
  4. $5.86$

Solution

Given, $\Delta m$ for ${ }_5 \mathrm{~B}^{11}=0.081 \mathrm{u}$ Number of nucleons $=11$ $ \begin{aligned} \text { Binding energy } & =931 \times \Delta m \mathrm{MeV} \\ & =931 \times 0.081 \\ & =75.411 \mathrm{MeV} \end{aligned} $ Average binding energy $ \begin{aligned} & =\frac{\text { binding energy }}{\text { number of nucleons }} \\ & =\frac{75.411}{11} \\ & =6.85 \mathrm{MeV} \end{aligned} $

Asked in: AP EAMCET 2008

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