If the mass defect of ${ }_5 \mathrm{~B}^{11}$ is $0.081 \mathrm{u}$, its average binding energy (in…
If the mass defect of ${ }_5 \mathrm{~B}^{11}$ is $0.081 \mathrm{u}$, its average binding energy (in $\mathrm{MeV}$ ) is
- $8.60$
- $6.85$
- $5.60$
- $5.86$
Solution
Given, $\Delta m$ for ${ }_5 \mathrm{~B}^{11}=0.081 \mathrm{u}$
Number of nucleons $=11$
$
\begin{aligned}
\text { Binding energy } & =931 \times \Delta m \mathrm{MeV} \\
& =931 \times 0.081 \\
& =75.411 \mathrm{MeV}
\end{aligned}
$
Average binding energy
$
\begin{aligned}
& =\frac{\text { binding energy }}{\text { number of nucleons }} \\
& =\frac{75.411}{11} \\
& =6.85 \mathrm{MeV}
\end{aligned}
$
Asked in: AP EAMCET 2008
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