If the mass defect of a nuclide is $3.32 \times 10^{-26} \mathrm{~g}$, its binding energy is $\mathrm{MeV}$

If the mass defect of a nuclide is $3.32 \times 10^{-26} \mathrm{~g}$, its binding energy is $\mathrm{MeV}$
  1. 9.31
  2. 18.62
  3. 27.93
  4. 37.24

Solution

Mass defect $=3.32 \times 10^{-26} \mathrm{~g}$ $=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \mathrm{amu}$ Binding energy $=$ Mass defect $\times 931 \mathrm{MeV}$ $=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \times 931=18.62 \mathrm{MeV}$

Asked in: AP EAMCET 2003

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