If the lines joining the origin to the points of intersection of a line $\mathrm{L}$ and…

If the lines joining the origin to the points of intersection of a line $\mathrm{L}$ and $\mathrm{x}^2+\mathrm{y}^2=4$ are the coordinate axes, then the equation of the line $\mathrm{L}$ is
  1. $x+y=2$
  2. $x+y=4$
  3. $x+y=1$
  4. $x+y=0$

Solution


$\because x^2+y^2=4 \Rightarrow x^2+y^2=2^2$ $\therefore$ Radius $\mathrm{r}=2$ So, the coordinate of the point $\mathrm{A}$ and $\mathrm{B}$ are $(2,0)$ and $(0,2)$ respectively. Then the equation of the required line is $\frac{x}{2}+\frac{y}{2}=1 \Rightarrow x+y=2$

Asked in: AP EAMCET 2023 (18 May Shift 1)

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