If the lines joining the origin to the points of intersection of a line $\mathrm{L}$ and…
- $x+y=2$
- $x+y=4$
- $x+y=1$
- $x+y=0$
Solution

$\because x^2+y^2=4 \Rightarrow x^2+y^2=2^2$ $\therefore$ Radius $\mathrm{r}=2$ So, the coordinate of the point $\mathrm{A}$ and $\mathrm{B}$ are $(2,0)$ and $(0,2)$ respectively. Then the equation of the required line is $\frac{x}{2}+\frac{y}{2}=1 \Rightarrow x+y=2$
Asked in: AP EAMCET 2023 (18 May Shift 1)