If the lines $2 x+y-3=0,3 x+2 y-2=0, k x-3 y-23=0$ are concurrent, then the roots of the equation $6 x^2-7…

If the lines $2 x+y-3=0,3 x+2 y-2=0, k x-3 y-23=0$ are concurrent, then the roots of the equation $6 x^2-7 x+k=0$ are
  1. $\frac{1}{2}, \frac{2}{3}$
  2. $2,3$
  3. $3,4$
  4. $6,2$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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