If the lines $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$ and $\frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}$ intersect each other, then value of $m$ is

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Aicharya · Accepted Answer

Two intersection lines are $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}=\lambda 	ext { and } \frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}=\mu$ From (1) and (2) $\lambda=0$ and $\mu=-1$ Then from (3), we get $m=-1$

If the lines $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$ and $\frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}$…

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