If the lines $3 x+4 y-5=0,2 x+3 y-4=0$ and $p x+4 y-6=0$ all meet at the same point, then $p$ is equal to

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Aicharya · Accepted Answer

$\begin{aligned} 3 x+4 y-5 & =0 \quad \ldots (i) \ 2 x+3 y-4 & =0 \quad \ldots (ii) \ \text {and } \quad p x+4 y-6 & =0 \quad \ldots (iii) \end{aligned}$ From Eqs. (i) and (ii), we get $x=-1, y=2$ So, $\quad-p+8-6=0 \Rightarrow p=2$

If the lines \(3 x+4 y-5=0,2 x+3 y-4=0\) and \(p x+4 y-6=0\) all meet at the same point, then \(p\) is equal…

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