If the line x = α divides the area of the region R = { x , y ∈ R 2 : x 3 ≤ y ≤ x ,…

If the line x=α divides the area of the region R={x,yR2:x3yx, 0x1} into two equal parts, then
  1. 12<α<1
  2. α4+4α2-1=0
  3. 0<α12
  4. 2α4-4α2+1=0

Solution

A= 01x-x3dx=14

Area of curvilinear triangle OPQ=A2=18

     01x-x3dx=18   2α4-4α2+1=0

   α2-12=12   α2=2-12

so α lies between 0.5 and 1

Asked in: JEE Advanced 2017 (Paper 2)

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