If the line $\frac{x+1}{2}=\frac{y-m}{3}=\frac{z-4}{6}$ lies in the plane $3 x-14 y+6 z+49=0$, then the value of $m$ is

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Aicharya · Accepted Answer

Line $\frac{x+1}{2}=\frac{y-m}{3}=\frac{z-4}{6}$ lies in plane $3 x-14 y+6 z+49=0$ $	herefore$ Point $(-1, \mathrm{~m}, 4)$ lies in the plane. $\begin{aligned} & 	herefore 3(-1)-14(\mathrm{~m})+6(4)+49=0 \Rightarrow-3-14 \mathrm{~m}+24+49=0 \ & 	herefore 14 \mathrm{~m}=70 \Rightarrow \mathrm{m}=5 \end{aligned}$

If the line $\frac{x+1}{2}=\frac{y-m}{3}=\frac{z-4}{6}$ lies in the plane $3 x-14 y+6 z+49=0$, then the…

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