If the line $p x-q y=r$ intersects the coordinate axes at $(a, 0)$ and $(0, b)$, then the value of $(a+b)$ is equal to

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Aicharya · Accepted Answer

We have, $p x-q y=r$ intersect the coordinates axes at $(a, 0)$ and $(0, b)$. $	herefore \quad p a=r \Rightarrow a=\frac{r}{p}$ $0-b q=r \Rightarrow b=\frac{-r}{q}$ $	herefore \quad a+b=\frac{r}{p}-\frac{r}{q}=\frac{r(q-p)}{p q}$

If the line $p x-q y=r$ intersects the coordinate axes at $(a, 0)$ and $(0, b)$, then the value of $(a+b)$…

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