If the lengths of two sides of a triangle are the roots of the equation $x^2-2 \sqrt{3} x+2=0$ and the angle…

If the lengths of two sides of a triangle are the roots of the equation $x^2-2 \sqrt{3} x+2=0$ and the angle between these sides is $\frac{\pi}{3}$, then the perimeter of the triangle is
  1. $2 \sqrt{6}+\sqrt{3}$
  2. $2 \sqrt{6}+2 \sqrt{3}$
  3. $\sqrt{6}+2 \sqrt{3}$
  4. $\sqrt{6}+\sqrt{3}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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