If the length of the pendulum in pendulum clock increases by 0 . 1 % , then the error in time per day is:

If the length of the pendulum in pendulum clock increases by 0.1%, then the error in time per day is:
  1. 43.2 s
  2. 8.64 s
  3. 86.4 s
  4. 4.32 s

Solution

T=2πlg

T∝l12

ΔTT=12Δll

ΔT24×3600=12×0.1100

ΔT=12×0.1100×24×3600

ΔT=43.2 s

Asked in: JEE Main 2021 (26 Aug Shift 2)

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