If the length of the major axis of the ellipse x 2 a 2 + y 2 b 2 = 1 is three times the length of minor axis…

If the length of the major axis of the ellipse x2a2+y2b2=1 is three times the length of minor axis, its eccentricity is
  1. 13
  2. 13
  3. 23
  4. 223

Solution

We have

x2a2+y2b2=1

Given,

Length of the major axis=3Length of the minor axis

2a=32b

a=3b

Now,

e=1-b2a2

e=1-b29b2

 e=1-19=83=223

Asked in: BITSAT 2019

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