If the length of an open organ pipe is $33.3 \mathrm{~cm}$, then the frequency of fifth overtone is [Neglect…
If the length of an open organ pipe is $33.3 \mathrm{~cm}$, then the frequency of fifth overtone is [Neglect end correction, velocity of sound $=333 \mathrm{~m} / \mathrm{s}$ ]
$3500 \mathrm{~Hz}$
$3000 \mathrm{~Hz}$
$2500 \mathrm{~Hz}$
$2000 \mathrm{~Hz}$
Solution
For a pipe open at both ends,
$\mathrm{n}=\frac{\mathrm{v}}{2 l}=\frac{333}{2 \times 33.3 \times 10^{-2}}=500 \mathrm{~Hz}$
$\therefore \quad$ Frequency of $5^{\text {th }}$ overtone,
$\mathrm{n}=6 \mathrm{n}=6 \times 500=3000 \mathrm{~Hz}$