If the kinetic energy of a moving body becomes four times its initial kinetic energy, then the percentage change in its momentum will be:

Question

Aicharya · Accepted Answer

K 2 = 4 &#160; K 1 1 2 m v 2 2 = 4 &#215; 1 2 m v 1 2 v 2 = 2 v 1 P = m v P 2 = m v 2 = 2 m v 1 P 1 = m v 1 % change = &#916; P P 1 &#215; 100 = 2 m v 1 - m v 1 m v 1 &#215; 100 = 100 %

If the kinetic energy of a moving body becomes four times its initial kinetic energy, then the percentage…

Solution