If the ionization enthalpy and electron gain enthalpy of an element are 275 and $86 \mathrm{kcal} \mathrm{mol}^{-1}$ respectively, then the electronegativity of the elementon the Pauling scale is:

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Aicharya · Accepted Answer

I.E. $+$ E.A. $=275+86=361 \mathrm{kcal} \mathrm{mol}^{-1}$ $=361 	imes 4.184=1510.42 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $	herefore \quad$ Electronegativity $=\frac{1510.42}{540}$ $=2.797=2.8$ ^

If the ionization enthalpy and electron gain enthalpy of an element are 275 and $86 \mathrm{kcal}…

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