If the function $f(x)=2 x^3-9 \mathrm{ax}^2+12 \mathrm{a}^2 \mathrm{x}+1$, where $\mathrm{a} \gt 0$, attains…

If the function $f(x)=2 x^3-9 \mathrm{ax}^2+12 \mathrm{a}^2 \mathrm{x}+1$, where $\mathrm{a} \gt 0$, attains its local maximum and local minimum values at $p$ and $q$, respectively, such that $\mathrm{p}^2=\mathrm{q}$, then $f(3)$ is equal to:
  1. 55
  2. 10
  3. 23
  4. 37

Solution

$f^{\prime}(x)=6 x^2-18 a x+12 a^2$
$f^{\prime}(x)=6\left(x^2-3 a x+2 a^2\right)$
roots are $a, 2 a$
$\mathrm{p}^2=\mathrm{q} \Rightarrow \mathrm{a}^2=2 \mathrm{a}$
$a=2$
$f(x)=2 x^3-18 x^2+48 x+1$
$f(3)=37$

Asked in: JEE Main 2025 (02 Apr Shift 1)

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