If the frequency of incident light falling on a metallic surface is doubled, maximum kinetic energy of…

If the frequency of incident light falling on a metallic surface is doubled, maximum kinetic energy of emitted photoelectrons
  1. increases to slightly more than double.
  2. remains the same.
  3. becomes twice.
  4. decreases to slightly more than double.

Solution

For a bullet of mass $m=20 \mathrm{~g}=0.02 \mathrm{~kg}$ moving with a velocity $v=200 \mathrm{~m} / \mathrm{s}$ : 1. Impulse $J$ : $J=m \times v=0.02 \times 200=4 \mathrm{Ns}$ 2. Average force $F_{\text {avg }}$ (assuming time $t=\frac{1}{50} \mathrm{~s}$ ): $F_{\mathrm{avg}}=\frac{J}{t}=\frac{4}{\frac{1}{50}}=200 \mathrm{~N}$ Thus, Answer (4): $4 \mathrm{Ns}, 200 \mathrm{~N}$ is correct.

Asked in: MHT CET 2020 (12 Oct Shift 2)

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