If the events $A$ and $B$ are independent, if $P\left(A^{\prime}\right)=\frac{2}{3}$ and…

If the events $A$ and $B$ are independent, if $P\left(A^{\prime}\right)=\frac{2}{3}$ and $P\left(B^{\prime}\right)=\frac{2}{7}$, then $P(A \cap B)$ is equal to.
  1. \(\frac{4}{21}\)
  2. \(\frac{1}{21}\)
  3. \(\frac{5}{21}\)
  4. \(\frac{3}{21}\)

Solution

$\begin{aligned} & P(A)=1-P\left(A^{\prime}\right)=1-\frac{2}{3}=\frac{1}{3} \\ & \text{and } P(B)=1-P\left(B^{\prime}\right)=1-\frac{2}{7}=\frac{5}{7} \end{aligned}$ Now if \(A\) and \(B\) are independent event then,
\(\mathrm{P}(\mathrm{A} \cap \mathrm{B})=\mathrm{P}(\mathrm{A}) \mathrm{P}(\mathrm{B})=\frac{1}{3} \cdot \frac{5}{7}=\frac{5}{21}\) $

Asked in: MHT CET 2020 (15 Oct Shift 1)

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