If the equilibrium constant for the reaction $2 A B ightleftharpoons A_2+B_2$ is 49 , what is the…

If the equilibrium constant for the reaction $2 A B ightleftharpoons A_2+B_2$ is 49 , what is the equilibrium constant for $A B ightleftharpoons \frac{1}{2} A_2+\frac{1}{2} B_2 ?$
  1. 7
  2. $\frac{1}{7}$
  3. 24.5
  4. 49

Solution

$\begin{array}{r}2 A B ightleftharpoons A_2+B_2 \\ K_c=\frac{\left[A_2ight]\left[B_2ight]}{[A B]^2}\end{array}$ again, $\quad \begin{aligned} A B & ightleftharpoons \frac{1}{2} A_2+\frac{1}{2} B_2 \\ K_c{ }^{\prime} & =\frac{\left[A_2ight]^{1 / 2}\left[B_2ight]^{1 / 2}}{[A B]} \\ K_c & =\left(K_c{ }^{\prime}ight)^2\end{aligned}$ or $\quad K_c{ }^{\prime}=\sqrt{K_c}=\sqrt{49}=7$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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