If the equations $$ \begin{aligned} & k x+(k+1) y+(k-1) z=0, \\ & (k-1) x+(k+2) y+k z=0 \text { and } \\ &…

If the equations $$ \begin{aligned} & k x+(k+1) y+(k-1) z=0, \\ & (k-1) x+(k+2) y+k z=0 \text { and } \\ & (k+1) x+k y+(k+2) z=0 \end{aligned} $$ have a non trivial solution, then the sum of all the possible values of $k$ is
  1. 0
  2. $-\frac{1}{2}$
  3. $\frac{1}{2}$
  4. 1

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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