If the equation $3 x^{2}+10 x y+3 y^{2}+16 y+k=0$ represents a pair of lines, then the value of $k$ is

If the equation $3 x^{2}+10 x y+3 y^{2}+16 y+k=0$ represents a pair of lines, then the value of $k$ is
  1. $-21$
  2. 21
  3. 12
  4. $-12$

Solution

Comparing the given equation with $a x^{2}+2 h x y+b y^{2}+2 g x+2 f y+c=0$, we get, $a=3, h=5, b=3, g=0, f=8, c=k$. Now, given equation represents a pair of lines. $\therefore a b c+2 f g h-a f^{2}-b g^{2}-c h^{2}=0$ $\therefore$ (3) (3) $(\mathrm{k})+2(8)(0)(5)-3(8)^{2}-3(0)^{2}-\mathrm{k}(5)^{2}=0$ $\therefore 9 \mathrm{k}+0-192-0-25 \mathrm{k}=0 \Rightarrow 16 \mathrm{k}=-192 \Rightarrow \mathrm{k}=-12$

Asked in: MHT CET 2020 (19 Oct Shift 2)

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