If the equation of transverse wave is $y = 5 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{40} \right)$ where, distance is in cm and time in second, then the wavelength of wave will be

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Aicharya · Accepted Answer

Here, $k = \frac{2\pi}{40} = \frac{2\pi}{\lambda}$ $	herefore$ Wavelength, $\lambda = 40	ext{ cm}$

If the equation of transverse wave is $y = 5 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{40} \right)$ where,…

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