If the equation of the base of an equilateral triangle is $x+y=6$ and the opposite vertex is the point $(-1…
- $\frac{8}{\sqrt{3}}$
- $32 \sqrt{3}$
- $\frac{32}{\sqrt{3}}$
- $16 \sqrt{3}$
Solution
Asked in: AP EAMCET 2020 (07 Oct Special)
Asked in: AP EAMCET 2020 (07 Oct Special)