If the equation $k x y+5 x+3 y+2=0$ represents a pair of lines, then $k=$
If the equation $k x y+5 x+3 y+2=0$ represents a pair of lines, then $k=$
- $\frac{15}{2}$
- $1, \frac{15}{2}$
- 15
- $40, \frac{-15}{2}$
Solution
Comparing given equation with
$\mathrm{Ax}^{2}+2 \mathrm{Hxy}+\mathrm{By}^{2}+2 \mathrm{Gx}+2 \mathrm{Fy}+\mathrm{c}=0$, we get
$\begin{aligned}
A &=0, B=0, C=2, F=\frac{3}{2} \cdot G=\frac{5}{2}, H=\frac{k}{2} \\
\Delta &=A B C+2 F G H-A F^{2}-B G^{2}-C H^{2}=0 \\
\Delta &=0+2 \frac{(3)}{2} \frac{(5)}{2}\left(\frac{k}{2}\right)-0-0-2\left(\frac{k}{2}\right)^{2}=0 \\
&=\frac{15}{4} k-\frac{k^{2}}{2}=0 \Rightarrow 15 k-2 k^{2}=0 \Rightarrow k(2 k-15)=0 \Rightarrow k=0, \frac{15}{2}
\end{aligned}$
Asked in: MHT CET 2020 (16 Oct Shift 1)
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