If the enthalpy and entropy change for a reaction at $298 \mathrm{~K}$ are $-145 \mathrm{~kJ}…

If the enthalpy and entropy change for a reaction at $298 \mathrm{~K}$ are $-145 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $-650 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ respectively, which one of the following statements is correct?
  1. $\Delta \mathrm{G}=-50 \mathrm{~kJ} \mathrm{~mol}^{-1}$, the reaction is spontaneous
  2. $\Delta \mathrm{G}=-48.7 \mathrm{~kJ} \mathrm{~mol}^{-1}$, the reaction is non-spontaneous
  3. $\Delta \mathrm{G}=+50 \mathrm{~kJ} \mathrm{~mol}^{-1}$, the reaction is spontaneous
  4. $\Delta \mathrm{G}=48.7 \mathrm{~kJ} \mathrm{~mol}^{-1}$, the reaction is non-spontaneous

Solution

$\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}$ We have, $\Delta \mathrm{H}=-145 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $\Delta \mathrm{S}$ $=-650 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ $\Rightarrow \Delta \mathrm{G}=\left(-145 \mathrm{~kJ} \mathrm{~mol}^{-1}\right)-298\left(-650 \times 10^{-3} \mathrm{~kJ}\right.$ $\left.\mathrm{mol}^{-1} \mathrm{k}^{-1}\right)=+48.7 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and the reaction is nonSpontaneous.

Asked in: AP EAMCET 2023 (17 May Shift 1)

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