If the elevation in boiling point of a solution of $10 \mathrm{~g}$ of solute $(\mathrm{mol}$. wt. $=100)$…

If the elevation in boiling point of a solution of $10 \mathrm{~g}$ of solute $(\mathrm{mol}$. wt. $=100)$ in $100 \mathrm{~g}$ of water is $\Delta \mathrm{T}_{\mathrm{b}}$, the ebullioscopic constant of water is
  1. 10
  2. $10 \Delta \mathrm{T}_{\mathrm{b}}$
  3. $\Delta \mathrm{T}_{\mathrm{b}}$
  4. $\frac{\Delta \mathrm{T}_{\mathrm{b}}}{10}$

Solution

$\begin{aligned} \Delta \mathrm{T}_{\mathrm{b}} &=\frac{\mathrm{K}_{\mathrm{b}} \times \mathrm{w} \times 1000}{\mathrm{M} \times \mathrm{W}} \\ \therefore \mathrm{K}_{\mathrm{b}} &=\frac{\Delta \mathrm{T}_{\mathrm{b}} \times 100 \times 100}{10 \times 1000}=\Delta \mathrm{T}_{\mathrm{b}} \end{aligned}$ .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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