If the electric flux entering and leaving an enclosed surface are $\phi_1$ and $\phi_2$ respectively, the…

If the electric flux entering and leaving an enclosed surface are $\phi_1$ and $\phi_2$ respectively, the electric charge inside the surface will be
  1. $\frac{\phi_2-\phi_1}{\varepsilon_0}$
  2. $\frac{\phi_1+\phi_2}{\varepsilon_0}$
  3. $\varepsilon_0\left(\phi_1-\phi_2\right)$
  4. $\varepsilon_0\left(\phi_2-\phi_1\right)$

Solution

Using Gauss's law, Net electric flux, $\Delta \phi=\frac{q}{\varepsilon_0}$ $q=\left(\phi_2-\phi_1\right) \varepsilon_0$

Asked in: MHT CET 2024 (04 May Shift 2)

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