If the eccentric angles of the extremeties of a focal chord (other than the major axis) of the ellipse $\frac{x^2}{25}+\frac{y^2}{9}=1$ are $\alpha$ and $\beta$ then $\frac{\cot \left(\frac{\alpha}{2} ight)}{ an \left(\frac{\beta}{2} ight)}=$

Question

If the eccentric angles of the extremeties of a focal chord (other than the major axis) of the ellipse $\frac{x^2}{25}+\frac{y^2}{9}=1$ are $\alpha$ and $\beta$ then $\frac{\cot \left(\frac{\alpha}{2}ight)}{	an \left(\frac{\beta}{2}ight)}=$

Aicharya · Accepted Answer

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If the eccentric angles of the extremeties of a focal chord (other than the major axis) of the ellipse…

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