If the distance $s$ travelled by a particle in time $t$ is given by $s=t^2-2 t+5$, then its acceleration is

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Aicharya · Accepted Answer

Given, $s=t^2-2 t+5$ On differentiating w.r.t., $t$ we get $\frac{d s}{d t}=2 t-2$ Again differentiating, we get $\frac{d^2 s}{d t^2}=2$

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