If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8 , then the…

If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8 , then the eccentricity is
  1. $\frac{1}{\sqrt{5}}$
  2. $\frac{1}{2}$
  3. $\frac{3}{5}$
  4. $\frac{4}{5}$

Solution

Here, $2 a e=6$ and $2 b=8 \Rightarrow b=4$ $\begin{aligned} & b^2=16 \\ & \Rightarrow \quad a^2\left(1-e^2\right)=16 \\ & \Rightarrow \quad \frac{9}{e^2}\left(1-e^2\right)=16 \\ & \Rightarrow \quad 9-9 e^2=16 e^2 \\ & \Rightarrow \quad 25 e^2=9 \\ & \end{aligned}$ $\Rightarrow \quad e=\frac{3}{5}$

Asked in: AP EAMCET 2009

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