If the displacement of a particle at a point is given by $s=3 t^{2}-12 t+14$, then the displacement of the…
If the displacement of a particle at a point is given by $s=3 t^{2}-12 t+14$, then the
displacement of the particle when its velocity becomes zero is
14 units
4 units
0 units
2 units
Solution
Given $\quad s \quad=3 t^{2}-12 t+14$
$v=\frac{d s}{d t}=6 t-12$
When $v=0$, we get $t=2$
$\therefore \mathrm{s}=(3 \times 4)-(12 \times 2)+14=12-24+14=2$ units