If the diodes are ideal in the circuit given below, then the current through the cell is
If the diodes are ideal in the circuit given below, then the current through the cell is
4 A
1.5 A
2 A
3 A
Solution
Diode, $D_1=$ reverse biased $(\mathrm{OFF})$
and diode, $D_2=$ forward biased $(\mathrm{ON})$.
Because diodes are ideal, so voltage drop across $\mathrm{D}_2$ is zero.
$\therefore$ Effective resistance, $R=3+2+3+2=10 \Omega$
Current through the cell,
$
I=V / R=20 / 10=2 \mathrm{~A}
$
