If the dielectric constant of a substance is $K=\frac{4}{3}$, then the electric susceptibility $\psi_{\mathrm{e}}$ is

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Aicharya · Accepted Answer

The dielectric constant permittivity and susceptibility are relative as, $\begin{aligned} & K=1+\frac{\chi_e}{\varepsilon_0} \Rightarrow \frac{4}{3}=1+\frac{\chi_e}{\varepsilon_0} \ & \Rightarrow \chi_e=\varepsilon_0\left(\frac{4}{3}-1ight) \ & \Rightarrow \quad \chi_e=\frac{\varepsilon_0}{3} \end{aligned}$ The electric susceptibility, $\chi_e=\frac{\varepsilon_0}{3}$

If the dielectric constant of a substance is $K=\frac{4}{3}$, then the electric susceptibility…

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